iMechanica - abaqus fracture toughness modelling //m.limpotrade.com/taxonomy/term/9058 en Cohesive element modelling problem in ABAQUS //m.limpotrade.com/node/23022

Dear All,

I am modelling a 3 point bend specimen with Cohesive elements tied to the upper and lower halves of the specimen in 2d.

The problem is that the CZ elements perform properly only for a combination of element sizes, i.e. a combination of element size of structure and CZ elements, for instance in my case the structure/specimen element size is 0.2mm and CZ is 0.001 or 0.002. For any other combination the adjacent elements bend as shown in the attached image.

I will be glad if someone could explain this behaviour and the solution.

I also attach the input file.

I am not sure about the node numbering issue of Cohesive elements. I meshed the elements assigning sweep path along normal to the crack propagation direction.

With regards,

Abhishek

AttachmentSize
Image icon CZbend.jpg391.23 KB
PDF icon ML4CZ1.pdf15.07 MB
Mon, 21 Jan 2019 10:11:49 +0000 hermatician 23022 at //m.limpotrade.com //m.limpotrade.com/node/23022#comments //m.limpotrade.com/crss/node/23022
Line Spring elements errors //m.limpotrade.com/node/19818 < div class = "字段field-name-body field-type-text -with-summary field-label-hidden">

Hello, All

***Problem ***

Failure pressure for Steam generator tube having 2 axial cracks. I am following one paper in that paper they found failure pressure by finding J and K values for line spring elements for different pressure. The pressure at which it approach material JIC(92N/mm) and KIC(65Mpa*sqrt(m)) value is considered as failure pressure or coalescence pressus

**Modelling**

I modeled steam generator tube having diameter of 22mm and thickness of 1.27 mm. It has 2 axial cracks of 6.35mm and lengths between cracks is 0.254mm. Length of the tube is 220mm, so I can assume it as a infinite cylinder.I modeled quarter symmetry of tube. I modified input file to create crack as a line spring elements, 31 line spring elements are created on crack. The tube has S8R shell elements.

**Material Property**

Material is Alloy 600.

Material property (Entered in ABAQUS): Elastic Modulus : 200 Gpa, Poission ratio : 0.3

Plastic property : Stress(MPa)Strain(mm/mm)

300 0

512 0.09274

687 0.178865

840 0.2582

946 0.33177

1125 0.5

1700 1.05

**Questions**

When I ran the analysis for 33Mpa my J reached value of 95 N/mm.And it shows 2 warnings.

1>The line spring elasticity predicts closing of the flaw at 2 points

2>The line spring plasticity theory is intended for tensile and opening moment loading of a flaw. 2 points have elastic stress states which violate this condition

Thank you for comment and advice on my post (crack using line spring elements)

I have one node that is showing stress singularity and it did't show up in warning when I monitor result. However when I went into job diagnostic it shows that one node has stress singularity I found that node and the node has boundary condition of Y symmetry. I am attaching image where node is located at. When i fixed that node it don't show any warnings in Job diagnostic but fixing the node is not realistic I think as I am using quarter symmetry.

if you have any another advice why this is happening or what else I can do to remove this warning I would really appreciate your help.

Thank you again.

Mon, 02 May 2016 21:53:47 +0000 bantijay01 19818 at //m.limpotrade.com //m.limpotrade.com/node/19818#comments //m.limpotrade.com/crss/node/19818
Smeared Crack and Cohesive zone modeling of concrete in ABAQUS //m.limpotrade.com/node/17658 < div class = "字段field-name-body field-type-text -with-summary field-label-hidden">

Can anybody help me in using smeared crack and cohesive zone modeling in concrete for different grades. I was actually facing problem in using the same to identify fracture parameters of concrete using ABAQUS. I will also be helpful if anyone let me know about an alternate method to find fracture parameters of concrete using ABAQUS apart from using models. Thanks in advance.......

星期一,2014年12月15日07:25:19 +0000 ram.jsk 17658 at //m.limpotrade.com //m.limpotrade.com/node/17658#comments //m.limpotrade.com/crss/node/17658
Fracture toughness test in Abaqus https://万博manbetx平台m.limpotrade.com/node/15241 < div class = "字段field-name-body field-type-text -with-summary field-label-hidden">

Hello,

I am currently working on fracture toughness of aluminium 2014. At the first stage an experiment of fracture toughness was carried out in order to identify the experimental results. The I model the specimen in Abaqus in order to compare experimental and FEA results. My question is how can i know what load i will use for the model? From experimental results I have that the maximum load was used for the specimen was 2kN. Am I going to use this value for load? Also the specimen is aluminium alloy 2014. I entered some material properties such as young modulus and poisson`s ratio. Are they enough or need to enter more material properties in order to get accurate results?

Kind Regards

Thu, 05 Sep 2013 08:29:07 +0000 George88b 15241 at //m.limpotrade.com https://万博manbetx平台m.limpotrade.com/node/15241#comments //m.limpotrade.com/crss/node/15241