I checked the main idea I had and its work

similar to the formula of the line crack, the 2 components of SIF are computed

For K-1=F1*σ√(a*∏)cos^(β)

the hole effect is known for mode-I (Bowie, Norman, Hsu, etc..)

F1 for each angle is normalised by the ratio of the concentration factor at each angle (see Paterson-Book), for example, F-1 for(β-60)= Kt-(β-60)/Kt-(β-90)

For shear component, the SIF for each angle is the always (2*K11) where KII is the stress intensity factor for β-45

Thanks